The height, h, in meters above the ground, of a projectile at any time, t, in seconds, after the launch is defined by the function h(t) = −6t2 + 15t + 2. the graph is shown below. when rounded to the nearest tenth, what is the maximum height reached by the projectile, how long did it take to reach its maximum height, and from what height was the projectile initially launched?

The equation sets the parabola. You can find the parabola vertex as:



then 



This means that the maximum height is 11.375 m and a projectilereaches this height at 1.25 seconds.

The projectile initially launched at time t=0, so the initial height is h(0)=2 m

Step-by-step explanation:

Knowing that you have to find two numbers that when they differ to 3, they also multiply to −4, and those numbers are −1 and 4. So, after clearing that up, you will have this [since our degree of this polynomial function is 4]:

Then, since is factorable, you will get this:

Finally, attach to the partially factored polynomial to get this:

I am joyous to assist you anytime.