pog2923
05.05.2020 •
Mathematics
The height of an object seconds after it is launched is modeled by the function h(t)=-4t^2+16t+180. When will the object hit the ground?
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Ответ:
9 seconds after the object is launched
Step-by-step explanation:
The function models the height of the object as a function of the time after the object is launched. Therefore h(t) will be zero, and you will solve for t like a normal quadratic equation.
0 = -4t² + 16t + 180
First, you can factor out the -4 from all the terms.
0 = -4(t² - 4t - 45)
Next, factor what is inside the parentheses
0 = -4 (t + 5) (t - 9)
Then you set each of the factors individually to zero and solve
t + 5 = 0 and t - 9 =0
From this we get that time is:
t = -5 and t = 9
Now that time cannot be negative, we figure out that the time is 9 seconds, therefore the object will hit the ground after 9 seconds.
Ответ: