Mathematics: The labor bureau wants to estimate, at a 90% confidence level, the proportion of all households that receive welfare. a preliminary sample showed that 17.5% of households in this sample receive welfare. the sample size that would limit the margin of error to be within 0.025 of the population proportion is:

The labor bureau wants to estimate, at a 90% confidence

shaniafuller29

12.01.2022

Sample size should be atleast 625

Step-by-step explanation:

Given that the Labor Bureau wants to estimate, at a 90% confidence level, the proportion of all households that receive welfare

Sample proportion = 17.5%

Let n be the sample size

Standard error of sample proportion= $\sqrt{\frac{pq}{n} } =\sqrt{\frac{0.175*0.825}{n} }$

Z critical for 90% = 1.645

Margin of error = 1.645 * std error

Since margin of error<0.025 we have

$1.645*\sqrt{\frac{0.175*0.825}{n} }$

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ReveenatheRaven2296

23.07.2022

Her got 60 pounds from North America

Step-by-step explanation:

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