The length of a rectangular field is 7 m less than 4 times the width. the perimeter is 136m ? . find the width and the length of the rectangle

➷ The perimeter is the total of all the lengths / widths

The lengths can be represented by 4x - 7

The width can be represented by x

2 times the length + 2 times the width would equal the perimeter

2(x) + 2(4x - 7) = 136

Simplify:

2x + 8x - 14 = 136

10x - 14 = 136

Add 14 to both sides:

10x = 150

Divide both sides by 10:

x = 15

The width is equal to 15m

The length is 4(15) - 7 = 53m

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we know that

the volume of the oblique pyramid with a square base is equal to

V=\frac{1}{3}BhV=

3

1

Bh

where

B is the area of the base

h is the height of the pyramid

In this problem

The area of the base is

B=EF^{2}\ units^{2}B=EF

2

units

2

h=AB\ unitsh=AB units

The two formulas to calculate h are

Applying the Pythagoras Theorem

h^{2}=AC^{2}-CB^{2}h

2

=AC

2

−CB

2

> h=\sqrt{AC^{2}-CB^{2}}h=

AC

2

−CB

2

h^{2}=AD^{2}-DB^{2}h

2

=AD

2

−DB

2

> h=\sqrt{AD^{2}-DB^{2}}h=

AD

2

−DB

2

therefore

the answer is

AB and EF

AC, CB and EF

AD, DB and EF