The length of a rectangular picture frame is twice it's width. we know that the perimeter of the rectangular frame is less than 48 inches. what is the maximum width the frame can be?

**write an expression for length in terms of width.

w=the width of the rectangular frame

*blank*=the lengh of the picture frame (write this expression using 'w'.)

*write and inequality to show how perimeter relates to length and width in terms of 'w'. show work, solve.

(i would use a picture but the app is acting up)

answer by the end of thursday october 20th in north american times.

For the first part:
if w is width and length is 2 times that, what would the length be? 

For the second part:
we know that the perimeter is less-than 48in, so we can start by saying 
something<48 
next you have to determine what that something is: the perimeter.
To find perimeter, you add the length of the sides. We already know that there are two sides which measure 'w' units, and two sides which measures are the expression you're finding in the first part. So, you simply need to add these together! 
width + width + length + length<48.
(Note: you'll obviously want to replace the words width and length with the values for the width and length; in the case of width, the value is given in the problem in the form of a variable, and the length is the expression you solve for in the first part. 

You should be able to solve to find the expression from the first part on your own, and once you have those, simply plug the value of the width and the length into the expression. Rather than just giving you the answer, this allows you to still work it out on your own to a certain extent.  

Make sense? (:

$1 to make
price is $2.50
This is a 250% increase.

If it costs $1.25 to make...
250% of $1.25 = $1.25 × 2.50 = $3.125 for the new price if we want to keep that 250% increase. Since there is no half cent, we round up to $3.13.

To maintain the gross margin percentage, we would have to up the unit selling price 63¢ to $3.13.