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Corgilover1234
02.07.2019 •
Mathematics
The length of rectangle is 6 feet greater than the width. the perimeter is 40 ft. find the dimensions of the rectangle.
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Ответ:
if L is 6 great than W
L=6+W
and P=40
subsitute 40 for P and 6+W for l
40=2(6+W+W)
40=2(6+2W)
divide both sides by 2
20=6+2W
minus 6 both sides
14=2W
divide both sides by 2
7=W
W=7
sub back
L=6+W
L=6+7
L=13
the rectangle has a length of 13ft and width of 7ft
Ответ:
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