![khalilattalah](/avatars/47889.jpg)
khalilattalah
11.11.2021 •
Mathematics
The length of the base of an isosceles triangle is 5x - 6 The length of a leg is x. The perimeter of the triangle is 153. Find x.
Solved
Show answers
More tips
- F Family and Home How to Get Rid of Your Neighbors?...
- S Society and Politics How Could Nobody Know About the Dead Mountaineers?...
- H Health and Medicine How to Cure Adenoids?...
- H Health and Medicine Why Wearing a Back Brace Can Be Beneficial During Back Strain?...
- S Sport When and Where Will the 2014 World Cup be Held?...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
Answers on questions: Mathematics
- M Mathematics To make a jug of plant fertilizer, Malika uses 6 cups of water and 3 scoops of fertilizer. Bart uses 8 cups of water and 5 scoops of fertilizer. Will Malika s and Bart s plant...
- M Mathematics You mix 1/2 quart of blue paint for every 3/4 quart of red paint to make 5 quarts of purple paint. How much blue paint and how much red paint do you use?...
- M Mathematics Simplify each expression. Radical Expressions...
- B Biology Task 2. Planning a Supervised Agricultural Experience Prepare a plan for carrying out an SAE in the AFN industry. The plan should include information about the following points:...
- M Mathematics Angle A is circumscribed about circle O. What is the measure of...
- A Arts Ok, this one s just for fun. It s a riddle. I want to see how many will get it. There are 4 parts to this riddle. Answer all four and label them. This is worth 20 points. 1....
Ответ:
Estimating value of √37.
We know that
6 < √37 < 7
If we take the average of 6 and 7, we get
Since,![6.5^{2} = 42.25](/tpl/images/0078/0474/9e94e.png)
6 < √37 < 6.5
If we take the average of 6 and 6.5 , we get
Since,![6.25^{2} = 39.0625](/tpl/images/0078/0474/80f82.png)
6 < √37 < 6.25
If we take the average of 6 and 6.25 , we get
Since,![6.125^{2} = 37.515625](/tpl/images/0078/0474/01006.png)
6 < √37 < 6.125
If we take the average of 6 and 6.125 , we get
Since,![6.0625^{2} = 36.75390625](/tpl/images/0078/0474/0786b.png)
6.0625 < √37 < 6.125
If we take the average of 6.0625 and 6.125 , we get
Since,![6.09375^{2} = 37.1337890625](/tpl/images/0078/0474/2efee.png)
6.0625 < √37 < 6.09375
If we take the average of 6.0625 and 6.09375 , we get
Since,![6.078125^{2} = 36.943603515625](/tpl/images/0078/0474/985c4.png)
6.078125 < √37 < 6.09375
If we take the average of 6.078125 and 6.09375 , we get
Since,![6.0859375^{2} = 37.03863525390625](/tpl/images/0078/0474/250c7.png)
Therefore,
√37 ≈ 6.0859375.
And if we round it to the nearest tenth, we get
√37 ≈ 6.1
Locating √37 on number line.
In order to locate √37 on number line first draw a line 0 to 6 on number line.
Then draw a perpendicular line segment of 1 unit on number 6 on number line.
Join the number 0 on the number line by the top point of perpendicular line segment on number 6 we drew in above step.
Finally, draw a curve by taking radius as Hypotenuse of the right trinagle form in the diagram shown.
The curve would cut the number line exactly at √37 on number line.