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rhondafits9000
28.07.2020 •
Mathematics
the mean cost of domestic airfares is RS 385 per ticket. Airfares were based on the total ticket value, which consisted of the price charged by the airlines plus any additional taxes and fees. Assume domestic airfares are normally distributed with a standard deviation of RS 110. What is the probability that a domestic airfare is RS 550 or more?
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Ответ:
0.0668
Step-by-step explanation:
Given the following :
Mean (m) Cost = RS385
Standard deviation (s) = RS110
Assume a normal distribution, Probability that domestic airfare is RS550 or more?
P(x > 550)
Find the z - score
Z - score = (x - m) / s
Where x = 550
Z = (550 - 385) / 110
Z = 165 / 110 = 1.5
P(Z > 1.5) = 1 - P(Z ≤1.5)
Using the z table : 1.5 = 0.9332
Therefore,
1 - P(Z ≤1.5) = 1 - 0.9332 = 0.0668
P(x > 550) = 0.0668
Ответ: