cyaransteenberg
04.08.2019 •
Mathematics
The mean of a normal probability distribution is 500; the standard deviation is 10. a. about 68 percent of the observations lie between what two values?
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Ответ:
P(Z=1)=0.8413
P(Z=-1)=0.1586
So P(Z=1)-P(Z=-1)=0.8413-0.1586=0.6827=68% approximately.
For Z=1 and Z-1, we have
X=mean +/- 1* standard deviation
=500 +/- 10
=> the range is
[490,510]
Ответ:
3
Step-by-step explanation:
51×1
17x1
=51/17
Simplifying 51/17, the answer is
=3