The National Center for Health Statistics interviewed 5409 adults smokers in 2015, and 2636 of them said they had tried to quit smoking during the past year. Consider this to be a random sample. a) Find a 95% confidence interval for the proportion of smokers who have tried to quit within the past year.

0.4740<p<0.5006

Step-by-step explanation:

-Given

#we calculate the proportion of trial quitters;

For a confidence level of 95%:

The confidence interval is calculated as follows:

Hence, the 95% confidence interval is 0.4740<p<0.5006

Lzzy has three more quarters ($0.25) than she has dimes ($0.10), twice as many nickels ($0.05) as she has dimes, and four times as many pennies ($0.01) as she has dimes.

Let us assume number of dimes = x.

"Three more quarters than dimes" would be = (x+3) quarters .

"Twice as many nickels as dimes " would be = (2x) nickels.

"Four times as many pennies as dimes" would be =(4x) pennies.

Total value of all coins = $7.61.

We can setup an equation now.

0.10*x + 0.25(x+3) + 0.05(2x)+0.01(4x)=7.61.

Let us simplify the equation.

0.10x + 0.25x + 0.75 + 0.10x + 0.04x = 7.61

0.49x + 0.75 = 7.61.

Subtratcing 0.75 from both sides, we get

0.49x = 6.86

Dividing both sides by 0.49, we get

x= 14.

Therefore,