![papoose10and11](/avatars/43701.jpg)
papoose10and11
18.07.2019 •
Mathematics
The next three batters on a baseball team have hit percentages of 0.325, 0.250, and 0.275, respectively. what is the probability that the first and third batters will both get a hit, while the second batter does not? a. 0.067 b. 0.201 c. 0.217 d. 0.603
Solved
Show answers
More tips
- H Health and Medicine Hangover: How to Get Rid of It Quickly?...
- A Auto and Moto How to Start a Diesel Engine in Cold Weather?...
- A Auto and Moto Which alarm system to choose?...
- P Photography and Videography What is lens calibration and why is it needed?...
- S Science and Technology How to Choose a Picture Frame: Tips and Recommendations...
- P Photography and Videography Understanding HDR: How It Works and Why You Need It...
- P Photography and Videography How to Choose the Perfect Photo Paper for Your Images?...
- C Computers and Internet How to Choose an Uninterruptible Power Supply (UPS) for Your Computer: Expert Tips...
- S Science and Technology How to choose a home theater system?...
- A Auto and Moto How to Choose a Car Wash? Tips and Recommendations...
Answers on questions: Mathematics
- M Mathematics I need help with this...
- M Mathematics Help me with this plzzzzz...
- H Health Which is an example of an unhealthy relationship a. abuse b. going on dates on a regular c. planning a future with him or her...
- C Chemistry Contour plowing, conservation plowing and crop rotation are ways to soil. a. prevent c. lose b. conserve d. none of the above...
- M Mathematics In a survey, 2 out of 8 students named math as their favorite subject. express the rate as a decimal and as a percent....
Ответ:
Option A. 0.067
Step-by-step explanation:
If three batters on a baseball team have hit percentages of 0.325, 0.250 and 0.275 respectively.
We have to calculate the probability that first and third batters will get a hit while second batter does not.
Since percentage of second batter to get a hit = 0.25
so percentage of second batter not to get a hit = (1 - 0.25)
Therefore, probability that the first and third batter to get a hit and second batter not to get a hit will be
=![P_{1}\times P_{3}\times P'_{2}](/tpl/images/1025/7188/df79a.png)
= 0.325 × 0.75 × 0.275
= 0.067
The Probability is 0.067 that the first and third batters will both get a hit, while the second batter does not.
Ответ: