The one below find the angle how do you do that one

If you have a quadratic equation  y = ax² + bx + c
Where  a, b, and c are constants.
The axis of symmetry is:    x = -b/2a

For f(x) = 2x² - 8x, comparing a=2, b = -8, c = 0
x  = -b/2a = -(-8)/(2*2) = 8/4 = 2.   Axis of symmetry or line of symmetry is x = 2

For g(x) = x² - 6x +1, comparing a=1, b = -6, c = 1.  (Note am taking the last term as +1, it still does not affect the answer if it is otherwise)
x  = -b/2a = -(-6)/(2*1) = 6/2 = 3.   Axis of symmetry or line of symmetry is x = 3

For h(x) = -2x²  comparing a=-2, b = 0, c = 0
x  = -b/2a = -(0)/(2*-2) = 0/-4 = 0.   Axis of symmetry or line of symmetry is x = 0

Ranking the axis of symmetry or line of symmetry from the least to the greatest:

x = 0, 2 , 3  That is:

h(x),  f(x), & g(x)