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asad92
25.03.2020 •
Mathematics
The percent of births to mothers with less than a college education in all of the most populated cities in the U.S. has an average of 39.3 with a standard deviation of 4.1. What is the probability that in a random sample of six cities, the sample mean would be more than 40?
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Ответ:
Probability that in a random sample of six cities, the sample mean would be more than 40 is 0.3372.
Step-by-step explanation:
We are given that the percent of births to mothers with less than a college education in all of the most populated cities in the U.S. has an average of 39.3 with a standard deviation of 4.1.
Assuming the data follows distribution. Also, a random sample of six cities is selected.
Firstly, Let
= sample mean of six cities
The z score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= average percent of births = 39.3
n = sample of cities = 6
Probability that in a random sample of six cities, the sample mean would be more than 40 is given by = P(
> 40)
P(
> 40) = P(
>
) = P(Z > 0.42) = 1 - P(Z
0.42)
= 1 - 0.66276 = 0.3372
Therefore, probability that the sample mean would be more than 40 is 0.3372.
Ответ: