orlando19882000
04.02.2020 •
Mathematics
The perimeter of a rectangle field is 340 yd. the length is 30 yd longer than the width. find the dimensions
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Ответ:
Lets assume:
Width=x
Length=x+30
2x+2(x+30)=340
2x+2x+60=340
4x+60=340
4x=280
x=70
Plugging x in:
Width=70
Length=100
Ответ:
2(l+w)=340, l=w+30
l+w=170
w+30+w=170
2w=140
w=70 yd.
l=70+30=100 yd
So the length of the rectangle field is 100 yd. and the width of the rectangle field is 70 yd. Hope it help!
Ответ:
The last option
Step-by-step explanation:
The last option