The perimeter of a rectangle is 15x + 17 y if the length is 7/2x + 7y then find the width of the rectangle a) 4x + 3/2y b) 8x + 3y c) 8x + 10y d) 4x + 3y

A)   The width of the rectangle is  = 4x + (3/2)y

Step-by-step explanation:

The perimeter of the rectangle = 15x + 17y

The length of the rectangle =

Let the width of the rectangle be W.

Now, Perimeter of the Rectangle is 2(L +W)

⇒  2(L +W)  =  15x + 17y

or, 2(  + W) = 15x + 17y

or,  7x + 14y + 2W  = 15x + 17y

or, 2W = 15x + 17y -( 7x + 14y)

⇒ 2W = 15x + 17y - 7x - 14y = 8x -3y

or, W =

or, Width of the rectangle  = 4x + (3/2)y

(x+6) (x-3)

Step-by-step explanation:

Set the difference first.

_x_= -18

_+_ = 3

6 x -3 = -18

6+(-3)= 3

Now distribute it with the x^2

(x+6) (x-3)

Tada!