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kirstenb278
04.01.2021 •
Mathematics
The perimeter of a rectangle is 64 feet. The length is two more than double the width. Find the dimensions of the rectangle.
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Ответ:
Length = 22 ; width = 10
Step-by-step explanation:
Perimeter of a rectangle = 2(length + width)
Perimeter = 64 feets
Length = 2 + (2*width)
Let :
Length = l ; width = w
Perimeter = 2((2 + (2w)) + w)
64 = 2(2 + 3w)
64 = 4 + 6w
64 - 4 = 6w
60 = 6w
w = 60/6
w = 10
Width = 10
Length = 2 + (2*width) = 2 + (2*10) = 2 + 20 = 22
Ответ: