The perimeter of a rectangle is 80 inches. The length is 4 inches longer than twice the width. What are the dimensions of the rectangle?

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 80cm

The length is 4 inches longer than twice the width is written as

l = 4 + 2w

Substitute this into the formula and solve for the width

That's

80 = 2( 4 + 2w) + 2w

80 = 8 + 4w + 2w

6w = 80 - 8

6w = 72

Divide both sides by 6

w = 12 cm

Substitute w = 12 cm into l = 4 + 2w

That's

l = 4 + 2(12)

l = 4 + 24

l = 28cm

Therefore

length = 28 cm

width = 12 cm

Hope this helps you

Step-by-step explanation:

The angle A is exterior in terms of the triangle with 30° angles.

The exterior angle is the sum of non - adjacent interior angles, therefore: