The perimeter of a soccer field is 304 yards. the area is 5,520 square yards. what are the dimensions of the field?

Area=legnth times width
perimiter=legnth+legnth+width+width
perimiter=2(legnth+width)

so
304=p=2(legnth+width
5520=area=legnth times width

so we have
304=2(l+w) and
5520=lw

304=2(l+w)
divide by 2 to simplify
152=l+w
subtract w
152-w=l

subsitute 152-w for l

5520=lw
5520=(152-w)(w)
distribute
5520=152w-w^2
subtract 152w from both sides
5520-152w=-w^2
add w^2 to both sides
w^2-152w+5520=0
factor the left side
(w-60)(w-92)=0
set each to zero
w-60=0
w=60
w-92=0
w=92
w=92 or 60

dimentions are
60 yd by 92 yd

In oder to answer this, you have to substitute x in f(x) for the equation in g(x). The substitution would look like this