The period t of a simple pendulum is given by t = 2π formula887.mml, where l is the length of the pendulum and g is the acceleration due to gravity. thus if l and t are measured, we can estimate g with g = 4π2l/t2. assume that the period is known to be t = 1.49 s with negligible uncertainty and that l is measured to be 0.559 ± 0.005 m. estimate g, and find the uncertainty in the estimate. note: when doing calculations, use pi = 3.1416.

Filling in the given numbers, you have

... g = 4(3.1416/1.49)²·0.559 ≈ 9.9403

The error is proportional to the length, so is

... ±∆g = ±(0.005/0.559)g = ±0.0889

The estimate for the value of g is 9.9403 ± 0.0889 m/s².

(7.5 x 10-10 kg) / (9.1 x 10-31 kg) ≅ 8.24 x 1020

Step-by-step explanation:

Divide the mass of one dust particle by the mass of one electron, and that will be your answer.

(7.5 x 10-10 kg) / (9.1 x 10-31 kg) ≅ 8.24 x 1020

hope this helps