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rhucke99121
26.02.2020 •
Mathematics
The Pew Research Center estimates that as of January 2014, 89% of 18-29 year olds in the United States use social networking sites.
1. Calculate the probability that at least 95% of 500 randomly sampled 18-29 year olds use social networking sites.
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Ответ:
0% probability that at least 95% of 500 randomly sampled 18-29 year olds use social networking sites.
Step-by-step explanation:
We use the binomial approximation to the normal to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that
,
.
In this problem, we have that:
1. Calculate the probability that at least 95% of 500 randomly sampled 18-29 year olds use social networking sites.
This probability is 1 subtracted by the pvalue of Z when X = 0.95*500 = 475. So
1 - 1 = 0
0% probability that at least 95% of 500 randomly sampled 18-29 year olds use social networking sites.
Ответ:
function
Step-by-step explanation: