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Jasten
22.09.2019 •
Mathematics
The point (0, 0) is a solution to which of these inequalities? a. y – 4 < 3x – 1 b. y – 1 < 3x – 4 c. y + 4 < 3x – 1 d. y + 4 < 3x + 1
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Ответ:
A
Step-by-step explanation:
Replace the point (0,0) in each inequality
A. y - 4 < 3x - 1
B. y - 1 < 3x - 4
C. y + 4 < 3x - 1
D. y + 4 < 3x + 1
A. 0 - 4 < 3(0) - 1
- 4 < - 1
True
B. 0 - 1 < 3(0) - 4
- 1 < - 4
False
C. y + 4 < 3x - 1
0 + 4 < 3(0) - 1
4 < - 1
False
D. y + 4 < 3x + 1
0 + 4 < 3(0) + 1
4 < 1
False
Ответ:
b = -![\frac{23}{15}](/tpl/images/1228/4269/d7440.png)
Step-by-step explanation:
- 15b - 25 = - 2
- 15b - 25 + 25 = - 2 + 25
- 15b = 23
- 15b ÷ - 15 = 23 ÷ - 15
b = -![\frac{23}{15}](/tpl/images/1228/4269/d7440.png)