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Anaaguayo954
29.09.2019 •
Mathematics
The point given is on the terminal side of an angle theta. find the exact values of the six trig functions of theta.. (-3,2)
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Ответ:
h =
sin (theta)= 2/√13
cos ( theta) = -3/√13
tan (theta) = -2/3
cot (theta ) = -3/2
sec (theta) = 1/cos(theta ) = -√13/3
csc(theta ) = 1/ sin (theta) = √13/2
Ответ:
Order pairs: (-2,-3), (1,6) and (2,9)
Step-by-step explanation:
y= 3x +3
y= 3(-2) + 3 = -3
y = 3 (1) + 3 = 6
y = 3(2) + 3 = 9
now just plug in the order pairs. remember quadrant I is (+,+) Q2 is (-,+) Q3 is (-,-) and Q4 is (+,-)