The points (3,9) and (-3,-9) lie in which quadrants?
A Quadrant I and II
B Quadrant I and II
C Quadrant II and III
D Quadrant III and IV

Quadrant I and III

Step-by-step explanation:

The coordinate (3,9) is all positive, therefore it lies in quadrant I.

The coordinate (-3,-9) is all negative, therefore it lies in quadrant III.

4340.

Step-by-step explanation:

14-5 = 9 and 23-14 = 9 so this is an arithmetic series with common difference of 9.

Sum of n terms = (n/2)[2a1 + d(n - 1)]

Here n = 31, d = 9 and a1 = 5.

So, substituting, we have:

Sum of 31 terms = (31/2)[2*5 + 9(31-1)]

= 15.5 * 280

= 4340.