The points (6, -3) and (7, -10) fall on a particular line. What is its equation in point-slope form? Use one of the specified points in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.

Step-by-step explanation:

Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;

The standard equation of a line is y = mx+c

m is the slope

c is the intercept

Get the slope;

m = Δy/Δx = y2-y1/x2-x1

m = -10-(-3)/7-6

m = -10+3/1

m = -7

Get the intercept;

Substitute the point (6, -3) and m = -7 into the expression y = mx+c

-3 = -7(6)+c

-3 = -42 + c

c = -3 + 42

c = 39

Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c

y = -7x + 39

Hence the required equation is y = -7x + 39

g = 4

Step-by-step explanation:

L.H.S. = 30

R.H.S. = 26 + g

In an equation , L.H.S. = R.H.S

So, 26 + g = 30

=> g = 30 - 26 = 4