Mathematics: The price of one share of a company declined $12 per day for 6 days. how much did the price of one share decline in total after the 6 days?

The price of one share of a company declined $12 - id12426970, dyamondgeorge1oy4nex

Ответ:

ineedhelpasap12

25.09.2022

$\frac{d}{dt} (x+y)=\frac{15}{2} \frac{ft}{s}$

Step-by-step explanation:

If we see the file attached. The lamppost and the person form a triangle. The hight of the triangles are set by 10 ft from the lamppost and 6 ft from the person.

We also know that the person moves at a rate of 3 $\frac{ft}{s}$

So, $\frac{dx}{dt} =3\frac{ft}{s}$

As we have similar triangles:

$\frac{6}{10} =\frac{y}{x+y}$

Solving the equation by y:

4y=6x

$y=\frac{3}{2}*x$

If we derivate the expression:

$\frac{dy}{dt} =\frac{3}{2}\frac{dx}{dt}$

Knowing that $\frac{dx}{dt} =3\frac{ft}{s}$

$\frac{dy}{dt} =\frac{3}{2}*(3)=\frac{9}{2}$

$\frac{d}{dt} (x+y)=\frac{dx}{dt}+\frac{dy}{dt}=3+\frac{9}{2} =\frac{15}{2} \frac{ft}{s}$

A6-ft-tall person walks away from a 10-ft lamppost at a constant rate of 3ft/sec. what is the rate t

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The price of one share of a company declined $12 per day for 6 days. how much did the price of one share decline in total after the 6 days?

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