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mathbrain58
02.09.2019 •
Mathematics
The probability that a student owns a car is 0.65, and the probability that a student owns a computer is 0.82. if he probability that a student owns both is 0.55, what is the probability that a given student owns neither a car nor a computer?
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Ответ:
If we draw a Venn diagram, we can see that the 0.55 is the intersection of probability owning a car and probability owning a computer. To solve for the probability that the student owns neither, we need to solve first for other variables.
The probability that a student owns a car but not a computer is:
P (owns a car but not computer) = 0.65 – 0.55 = 0.10
The probability that a student owns a computer but not a car is:
P (owns a car but not computer) = 0.82 – 0.55 = 0.27
Therefore the probability of owning neither is:
P (own neither) = 1 – 0.10 – 0.27 – 0.55
P (own neither) = 0.08
Therefore there is a 8% probability that the student owns neither a car or a computer.
Ответ:
*>/= : it's the greater than or equal sign