Mathematics: The product of (x+p)(x+q) can be written as x^2+(p+q)x+pq. An intermediate step in this multiplication is x^2+px+qx+pq=x^2+(p+q)x+pq. Explain why px+qx=(p+q)x. I m Really confused please help!

The product of (x+p)(x+q) can be written as x^2+(p+q)x+pq.

keving4three

28.01.2022

px+qx=(p+q)x by taking out the common factors.

Step-by-step explanation:

It is given that the product of (x+p)(x+q) is x^2+(p+q)x+pq .

Given expression is

(x+p)(x+q)

Using distributive property, we get

x(x+q)+p(x+q)

x(x)+q(x)+p(x)+p(q)

x^2+qx+px+pq

In middle terms px and qx the highest common factor is x. So taking out common factor from middle terms we get

x^2+x(q+p)+pq

It can be written as

x^2+x(p+q)+pq

Therefore, px+qx=(p+q)x by taking out the common factors.

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valeriekbueno

15.11.2020

when x=3: answer is 1

when x=0: answer is 1

when x=5: answer is 1

Step-by-step explanation:

Substitute the given value into the function and evaluate.

I hope this helped!!

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It's ok id u don't...lol

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