The quadratic x^2+7x+20$ has the same roots as the quadratic ax^2+bx+1 what is a+b?

If f(x)=x^2+7x+20 has the same roots as g(x)=Ax^2+Bx+1, then

one must be a multiple of the other.

By comparison of the constant terms, we know that 20g(x)=f(x), or

g(x)=(1/20)f(x)

=(1/20)(x^2+7x+20)

=(1/20)x^2 + (7/20)x + 20/20

=(1/20)x^2 + (7/20)x + 1

Therefore A=(1/20), B=(7/20),  and A+B=(1+7)/20=8/20=2/5

b(-1)= -6

b(0)= -4

b(4)=  4

Step-by-step explanation:

2(-1) - 4

-2-4=-6

2(0) - 4

0 - 4 = -4

2(4) - 4

8 - 4 = 4