The rectangular front windshield of the bus has the length of 1.5√3 m and the width of 1.5 m . The wipers are attached to the bottom corners. If the length of each wiper is equal to the width of the windshield, find the percentage of the windshield that wipers can reach. (Solve this task without using Trigonometry)

See the attached sketch. From their respective corners, each wiper sweeps out a portion of the total area of the windshield equal to the area of a quarter-circle with radius 1.5 m (shaded green), and they overlap in a half-lens-shaped region (shaded red). The area that the wipers together cover is equal to the sum of the green areas minus the area of the red overlap. It's easy to see that this red area is equal to the area of the highlighted circular segment (bordered in blue).

Not sure how exactly you can avoid finding the area of the segment without resorting to trigonometry, though... The radii AC and AD form an angle θ such that the segment has area

1/2 (1.5 m)² (θ - sin(θ))

but you can avoid mentioning the sine function by writing it as

1/2 (1.5 m)² (θ - √3/2)

which follows from

sin(θ) = 2 sin(θ/2) cos(θ/2) = 2 ((BD/2)/AB) ((AC/2)/AB)

and the fact that BD has length equal to the radii, since by the Pythagorean theorem

(AC/2)² + (BD/2)² = AB²

(whether this theorem falls under trigonometry is also up for debate)

You would need trig to find the measure of the angle θ as well, unless you just take for granted the fact that a triangle with side lengths 1.5√3/2, 1.5/2, and 1.5 (i.e. AC/2, BD/2, and AB), since they occur in a ratio of √3 : 1 : 2 is a 30°-60°-90° triangle, so that θ = 60° = π/3 rad.

At any rate, the percentage is about (2×(quarter-circle area) - (segment area))/(rectangle area) = 85.46%, since

• area of rectangle = (1.5 √3 m) • (1.5 m) ≈ 3.897 m²

• area of quarter-circle = π/4 (1.5 m)² ≈ 1.767 m²

• area of segment = 1/2 (1.5 m)² (π/3 - √3/2) ≈ 0.204 m²

≈ 85.46%

Step-by-step explanation:

Refer to attached

The area of coverage is the sum of two sectors of 60° and a triangle.

Find each area and calculate the percentage of covered region

Rectangle area:

A = 1.5*1.5√3 = 9√3/4 ≈ 3.8971

Triangle height

h = √1.5² - (1/2*1.5√3)² = √1/4*1.5² = 1.5/2 = 3/4Since h is half of the hypotenuse, the opposite angle is 30°This leaves each sector 60°

Triangle area

A = 1/2*1.5√3*3/4 = 9√3/16 ≈ 0.9742

Sectors' area

A = 2*1/6*πr² = 1/3π(1.5)² = 3π/4 ≈ 2.3561

Area covered by wipers

A = 0.9742 + 2.3561 = 3.3303

Percentage of covered region:

3.3303/ 3.8971*100% ≈ 85.46%

I believe the answer would be A. C=200x+ 70. Hope this helps!