jonallere04
13.02.2021 •
Mathematics
The roots a and ß of the quadratic equation x2-5x+3(k-1)=0 are such that a- B=1. Find the value k.
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Ответ:
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Step-by-step explanation:
let x=1
now,
(1)×2-5×(1)+3(k-1)=0
2-5+3(k-1)=0
2-5+3k-3=0
2-8+3k=0
-6+3k=0
3k=6
k= 2
Ответ: