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05.03.2020 •
Mathematics
The roots of the quadratic equation z^2 + az + b = 0 are -7 + 2i and -7 - 2i. What is a+b?
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Ответ:
a+b=249/14
Step-by-step explanation:
z1= [-a+sqrt(a^2-4ab)]/2
z1= [-a-sqrt(a^2-4ab)]/2
z1= -a/2+[sqrt(a^2-4ab)]/2
then,
-a/2=-7
so, a=14
a^2-4ab= -16
b=(a^2+16)/(4a)
b=53/24
therefore, a+b= 249/14
Ответ:
D
Step-by-step explanation:
angle 1 does not equal to angle 4
angle 1 does not equal to 2 since 1 is acute while 2 is a obtuse
angle 1 is adjacent from 3 so its true the angles are the same