The scatter plot below shows the relationship between

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jettskii214

26.07.2019

Short answer: quadratic < < < < well it sure isn't linear. it's not a straight line.and it's not an absolute value graph. they look quite different. they are sort of v shaped using straight lines. sort of like an angel symbol. it might be a quadratic. i've checked this out and it looks closer to a quadratic. desmos plots these things so i'll give you what it looks like. none of them look like the fit the data. using the data we have, the quadratic that best fits the data is y = 0.0193^2 + 0.3814x - 0.0639the data points are not supper accurate so this graph is just a little off from what the points suggest. also should not be negative no matter how small a negative. i have included a graph for these points. i have also used the solution of 3 equations with three unknowns using the following sets of dataa b c d225 15 1 10625 25 1 201225 35 1 35solving these three equations gives the quadratic i have listed. a graph is enclosed in the answer. note: since this represents a physical property, don't go into the 0> x values because it wall have no meaning physicicallyquadratic < < < < answer

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Ответ:

shadow29916

26.07.2019

Mathematics

the answer is: exponential.

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Manuel2019

02.12.2021

Mathematics

$(1+\sec b)(\sec b - 1) = \dfrac{\sin b \sec b}{\cos b \csc b}$ focusing on the right-hand side: $\text{rhs} = \dfrac{\sin b \sec b}{\cos b \csc b}$ by definition, $\csc b = \frac{1}{\sin b}$ and $\sec b = \frac{1}{\cos b}$ . $\begin{aligned} \text{rhs} & = \dfrac{\sin b \sec b}{\cos b \csc b} \\ & = \dfrac{\sin b \cdot \frac{1}{\cos b}}{\cos b \cdot \frac{1}{\sin b}} \\ & = \dfrac{\frac{\sin b}{\cos b}}{ \frac{\cos b}{\sin b}} \end{aligned}$ this is really just division, which means multiply by reciprocal. $\begin{aligned} \text{rhs} & = \dfrac{\frac{\sin b}{\cos b}}{ \frac{\cos b}{\sin b}}\\ & = \dfrac{\sin b}{\cos b} \div \dfrac{\cos b}{\sin b} \\ & = \dfrac{\sin b}{\cos b} \cdot \dfrac{\sin b}{\cos b} \\ & = \dfrac{\sin^2 b}{\cos^2 b} \end{aligned}$ ======focusing on the left-hand side, expand out: $\begin{aligned} \text{lhs} & = (1 +\sec b)(\sec b - 1) \\ & = 1(\sec b - 1) +\sec b(\sec b - 1) \\ & = \sec b - 1 + \sec^2 b - \sec b \\ & = - 1 + \sec^2 b \\ & = \sec^2 b - 1 \end{aligned}$ this is an alternate form of a pythagorean identity.if we have $\sin^2 b + \cos^2 b = 1$ , dividing everything by secant gets us $\begin{aligned} \tfrac{\sin^2 b}{\cos^2 b} + 1 & =\tfrac{1}{\cos^2 b} \\ \tfrac{\sin^2 b}{\cos^2 b} + 1 & =\sec^2 b \\ \tfrac{\sin^2 b}{\cos^2 b} & = \sec^2 b - 1 \end{aligned}$ hence $\begin{aligned} \text{lhs} & = \sec^2 b - 1 \\ & = \frac{\sin^2 b}{\cos^2 b} \\ & = \text{rhs} \end{aligned}$ also, $\frac{\sin^2 b}{\cos^2 b} = \tan^2 b$

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The scatter plot below shows the relationship between the saturation specific humidity, in grams per kilogram of air, and the ambient temperature, in degrees celsius, of the atmosphere. which type of function would best model this data?exponential linear absolute value quadratic

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