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kehrieheb9526
19.05.2020 •
Mathematics
The scores for the Algebra 2 CFE are normally distributed with a mean score of 45 and a standard deviation of 5.6. If you score 52 on the test, what percentage of test takers scored lower than you?
87.49 %
89.44 %
90.32 %
91.15%
Solved
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Ответ:
89.44%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
If you score 52 on the test, what percentage of test takers scored lower than you?
This is the pvalue of Z when X = 52.
So 89.44% of test takers scored lower than you.
Ответ:
how about you stop being confused
Step-by-step explanation:
just read the question