The second side of a triangular deck is 3 feet longer than the shortest side, and the third side is 3 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 72 feet, what are the lengths of the three sides?

The length of the shortest side is 18 ft

The length of the second side is 21 ft

The length of the third side is 33 ft

Step-by-step explanation:

Let

x > the length of the shortest side

y > the length of the second side

z > the length of the third side

we know that

The perimeter of the deck is

P=x+y+z

P=72 ft

so

72=x+y+z > equation A

y=x+3 > equation B

z=2x-3 > equation C

substitute equation B and equation C in equation A and solve for x

72=x+(x+3)+(2x-3)

72=4x

x=72/4

x=18 ft

Find the value of y

y=18+3=21 ft

Find the value of z

z=2(18)-3=33 ft

therefore

The length of the shortest side is 18 ft

The length of the second side is 21 ft

The length of the third side is 33 ft

There were 130 hamburgers sold on Friday

Step-by-step explanation:

Assume that the number of hamburgers sold is x

∵ The number hamburgers sold = x

∵ The number of cheeseburgers sold was two times the number of

   hamburgers sold

∴ The number of cheeseburgers sold = 2x

∵ On Friday, the shop sold a combined total of 390 hamburgers and

    cheeseburgers

→ Add x and 2x, then equate the sum by 390

∴ x + 2x = 390

→ Add the like terms

∴ 3x = 390

→ Divide both sides by 3

∵ =

∴ x = 130

∵ x represents the number of hamburgers

∴ There were 130 hamburgers sold on Friday