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MK100
12.09.2019 •
Mathematics
The solution of a certain differential equation is of the form y(t)=aexp(7t)+bexp(11t), where a and b are constants. the solution has initial conditions y(0)=1 and y′(0)=4. find the solution by using the initial conditions to get linear equations for a and b.
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Ответ:
Step-by-step explanation:
Given that the solution of a certain differential equation is of the form
Use the initial conditions
i) y(0) =1
ii) y'(0) = 4
Find derivative of y first and then substitute
Now using I and II we solve for a and b
Substitute b = 1-a in II
Hence solution is
Ответ:
The whole segment is AC,AC=7,BC=5.
AB=?
AC-BC=AB
7-5=2