The solution to the system equations

Let's solve this system of equations through substitution.

We have these two equations.

-7x-2y=14

6x+6y=18

Now let divide the second equation by 6.

6x+6y=18 >   x+y=3

Next, let us move y to the right side of the equation.

x+y=3 > x=3-y (x equals 3-y)

Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.

-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)

We have a one variable equation now and can solve for y.

-7(3-y)-2y=14

-21+7y-2y=14

5y=35

y=7

Plug in 7 for y in any equation to find x.

x+y=3

x+7=3

x=-4

x=-4, y=7

(36) (x+6) (-10 or -2) i got this right on (ed)

Step-by-step explanation:

1 Add  to both sides of the equation. The value of  in this equation is 36.

2 Write the left side of the equation as a binomial squared. The left side of the equation becomes (x +6)2.

3 Use the square root property of equality.

4 Isolate the variable: x = -10 or -2