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potatocow
24.07.2019 •
Mathematics
The standard form of the equation of a circle is (x−3)2+(y−1)2=16. what is the general form of the equation? a- x2+y2−6x−2y−26=0 b- x2+y2+6x+2y+26=0 c- x2+y2−6x−2y−6=0 d- x2+y2+6x+2y−6=0
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Ответ:
the general form of the equation of a circle is
ax² + by² + cx + dy + e = 0
we have
(x−3)²+(y−1)²=16
x²-6x+9+y²-2y+1=16
x²+y²-6x-2y-6=0
the answer is the option
C) x2+y2−6x−2y−6=0
Ответ:
The expression (20 - w)w represents the area of the garden in square meters.
The perimeter of the garden = 40 meters
The width = w
Perimeter of a rectangle = 2(l + w)
Hence,
40 = 2(l + w)
20 = l + w
The length of the garden = 20 - w
Since width = w and length = 20 - w
Recall, the area of a rectangle = Length × width
Area of the rectangular garden is expressed thus :
(20 - w) × w = (20 - w)w
Hence, the expression represents the area of the garden in square meters.
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