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tae8002001
09.11.2019 •
Mathematics
The sum of four consecutive odd integers is –72. write an equation to model this situation, and find the values of the four integers. a. n – (n + 2) – (n + 4) – (n + 6) = –72; n = –20; n + 2 = –18; n + 4 = –16; n + 6 = –14 b. n + (n – 2) + (n – 4) + (n – 6) = –72; n = – 21; n – 2 = –23; n – 4 = –25; n – 6 = – 27 c. n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –23; n + 4 = –25; n + 6 = –27 d. n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –19; n + 4 = –17; n + 6 = –15
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Ответ:
D.![n + n + 2 + n + 4 + n + 6 = -72; n = -21; n + 2 = -19; n + 4 = -17;n + 6=-15](/tpl/images/0366/3011/111e4.png)
Step-by-step explanation:
Given:
The sum of four consecutive odd integers is -72.
Let the 4 consecutive odd integers be![n,n+2,n+4,\textrm{ and }n+6](/tpl/images/0366/3011/011d6.png)
Now, as per question,
Therefore, the consecutive integers are:
Hence, the correct option is option D.
Ответ:
Step-by-step explanation:
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