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linhlema2005
03.07.2019 •
Mathematics
The sum of four consecutive odd integers is –72. write an equation to model this situation, and find the values of the four integers. n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –19; n + 4 = –17; n + 6 = –15 n + n + 2 + n + 4 + n + 6 = –72; n = –21; n + 2 = –23; n + 4 = –25; n + 6 = –27 n – (n + 2) – (n + 4) – (n + 6) = –72; n = –20; n + 2 = –18; n + 4 = –16; n + 6 = –14 n + (n – 2) + (n – 4) + (n – 6) = –72; n = – 21; n – 2 = –23; n – 4 = –25; n – 6 = – 27
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Ответ:
n + n + 2 + n + 4 + n + 6 = –72
4n +12 = -72
subtract 12 from each side
4n = -84
divide by 4
n = -21
-21,-19,-17,-15
Ответ:
83
Step-by-step explanation:
68-(-15)=68+15=83