The sum of the ages of a brother and sister is 23. If four times the brother's age is subtracted from three times the sister's age, the difference is 27. 1: The sum of the ages of a brother and sister is 23. Give an equation that represents this statement using bbb as the age of the brother and s as the age of the sister. If four times the brother's age is subtracted from three times the sister's age, the difference is 27. Give an equation that represents this statement using bbb as the age of the brother and s as the age of the sister. Using your answers from parts B and C, what are the ages of the brother and sister, respectively?

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Ответ:

cathysilvestro

09.11.2021

Mathematics

The two numbers are 12 and 26

Step-by-step explanation:

let the first number = a

let the second number = b

The ratio of the numbers is given as;

$\frac{a}{b} = \frac{6}{13} \\\\a = \frac{6b}{13}$ -------- (1)

The lcm of the two numbers is given as;

a x b = 312

ab = 312 --------- (2)

From equation (1), $a = \frac{6b}{13}$

$b(\frac{6b}{13} ) = 312\\\\\frac{6b^2}{13} = 312\\\\6b^2 = 4056\\\\b^2 = \frac{4056}{6} \\\\b^2 = 676\\\\b = \sqrt{676} \\\\b = 26\\\\From \ equation \ (1);\\\\a = \frac{6b}{13} \\\\a = \frac{6 \times 26}{13} \\\\a = 12$

Therefore, the two numbers are 12 and 26

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