The sum of the digits of a two digit number is 10. If 36 is subtracted from the number, the digit interchange their places Find the number

Step-by-step explanation:

Let A be the tens digit of the number and B be the ones digit.

We have A + B = 10 and 10A + B - 36 = 10B + A.

=> A + B = 10 and 9A - 36 = 9B

=> A + B = 10 and A - 4 = B

=> A + B = 10 and A - B = 4

Therefore 2A = 10 + 4 = 14,

A = 7 and B = 10 - 7 = 3.

Hence the number is 73.

Step-by-step explanation:

4 + 5x + x + 2  =  180   {linear pair}

5x + x + 4 + 2 = 180  {Combine like terms}

      6x + 6   = 180  {Subtract 6 form both sides}

              6x = 180 - 6

              6x = 174   {Divide both sides by 6}

                x = 174/6

x = 29

x + 2 = 29 + 2 = 31

5x + 4 = 5*29 + 4 = 145 + 4 = 149

2) 6x + 4 + 32 = 90   {Complementary angles}

           6x + 36 = 90   {Subtract 36 from both sides}

                   6x = 90 - 36

                    6x = 54       {Divide both sides by 6}

                      x = 54/6

x = 9

6x + 4 = 6*9 + 4 = 54 + 4 = 58