The sum of the square of two consecutive positive integers is 85. Write a quadratic equation​

2x^2 + 2x - 83 = 0

Step-by-step explanation:

Consecutive integers differ by 1

Let the first number be x

The next will be (x+1)

The sum of the squares of these two numbers is 85

so we have;

x^2 + (x + 1)^2 =85

= x^2 + x^2 + 2x + 2 = 85

2x^2 + 2x + 2-85 = 0

2x^2 + 2x - 83 = 0

1st box is (2x+1)-(-x^2+3x)    2nd box is x^2 - x + 1

Step-by-step explanation:

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