The sum of three consecutive integers is -96. what is the smallest integer

Let the smallest number be x.

x + x + 1 + x + 2 = -96
3x + 3 = -96
3x = -99
x = -33

The smallest number is -33

Hi there

Let Three consecutive be x , x + 1 and x + 2

According to the question

x + x + 1 + x + 2 = -96

→ 3x + 3 = -96

→ 3x = -99

→ x = - 33

Thus , First number , x is = - 33

second number = x +1 = -33 + 1 = -32

Third number = x + 2 = -33 + 2 = -31

Hope this helps you

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