The system of conics has two solutions. (x−2)^2 + (y−3)^2 = 16 (x−2)^2/16 + (y−3)^2/64 = 1 What are the solutions to this system of conics?

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Ответ:

des7900

04.11.2022

Mathematics

Step-by-step explanation:

The distance between the point anywhere in the circumference of the circle and the centre of the circle is 2,

$\sqrt{(1 - x {)}^{2} + {(3 - y)}^{2} } = 2 \\ 1 - 2x + {x}^{2} + 9 - 6y + {y}^{2} = 2 \\$

Therefore the equation of circle is:

${x}^{2} + {y}^{2} - 2x - 6y + 8 = 0$

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