AgentPangolin

28.08.2019 • 

Mathematics

The table below includes results from polygraph (lie detector) experiments conducted by researchers. in each case, it was known if the subjected lied or did not lie, so the table indicates when the polygraph test was correct. use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. do the results suggest that polygraphs are effective in distinguishing between truth and lies?
did the subject actually lie?
no (did not lie)
yes (lied)
polygraph test indicated that the subject lied.
9
23
polygraph test indicated that the subject did not lie.
10
8
χ2equals=
p-value=
do the results suggest that polygraphs are effective in distinguishing between truth and lies?
a.there is not sufficient evidence to warrant rejection of the claim that whether a subject lies is independent of the polygraph test indication.
b.there is sufficient evidence to warrant rejection of the claim that whether a subject lies is independent of the polygraph test indication.
c.there is not sufficient evidence to warrant rejection of the claim that polygraph testing is 95% accurate.
d.there is sufficient evidence to warrant rejection of the claim that polygraph testing is 95% accurate.

Ответ:

catdog5225

01.01.2022

Mathematics

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The best and most correct answer among the choices provided by the question is the second choice or letter B.

"There is sufficient evidence to warrant rejection of the claim that whether a subject lies is independent of the polygraph test indication." suggests that polygraphs are effective in distinguishing between truth and lies.

I hope my answer has come to your help. God bless and have a nice day ahead!

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Ответ:

lucasrandall

29.04.2021

Mathematics

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Let P be the proportion of correct results of all polygraph results H0: P ≥ 0.80 Ha: P < 0.80 Estimated p = 74 / 98 = 0.7551 Variance of proportion = p*(1-p)/n = 0.8(0.2)/98 =0.0016327 S.D. of p is sqrt[0.001633] = 0.0404 z = ( 0.7551 - 0.8 ) / 0.0404 = -1.1112 P-value = P( z < -1.1112) = 0.1335 Since the p-value is greater than 0.05, we do not reject the null hypothesis. Based on the results there is no evidence that polygraph test results should be prohibited as evidence in trials.

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