The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did not report fatigue.

Which calculation shows that selecting a subject who took the drug and selecting a subject who reported fatigue are dependent events?

Choose all answers that are correct.

— P(drug) = 0.6
P(drug | fatigue) ≈ 0.727
0.6 ≠ 0.727

— P(fatigue) = 0.44
P(fatigue | drug) ≈ 0.533
0.44 ≠ 0.533

— P(drug) = 0.6
P(fatigue) ≈ 0.44
0.6 ≠ 0.44

—P(drug and fatigue) = 0.32
P(drug) • P(fatigue) = 0.264
0.33 ≠ 0.264

Therefore, the correct options are;

-P(fatigue) = 0.44

= 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

From the options, we have;

= 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

= 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

We are given

a thermal conductivity rate of 0.03 watts (W) per meter(m) per degree celsius

so, thermal conductivity is

while we want the batting thermal conductivity in  w/cm•c

The only difference is that metre and cm

so, we need to change metre into centimeter

we know

1m =100cm

so, we can write thermal conductivity as

we can replace 1m as 100cm

now, we can simplify it

so, thermal conductivity is

................Answer