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volocibel
27.08.2020 •
Mathematics
The three sides of a triangle are 4cm, 6cm and 8cm.
(a) find the cosine of the largest angle
(b) show that the area of the triangle is 3√15cm²
(c) find the length of the shortest altitude of the triangle
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Ответ:
In bold below.
Step-by-step explanation:
(a) The largest angle is opposite the largest side.
So by the Cosine Rule:
8^2 = 4^2 + 6^2 - 2*4*6 cos x
cos x = (8^2 - 4^2 - 6^2) / (-2*4* 6)
= -0.25.
x = 104.48 degrees.
(b) Area of the triangle = 1/2 * 4 * 6 sin 104.48
= 11.62
= 3 √15.
(c) The shortest altitude will have the longest sides as the base.
Area = 1/2 * altitude * base
3√15 = 1/2 * 8 * a
a = 3√15 / 4 cm
= 0.75√15 cm.
Ответ: