The time an object is in free fall is given by the formula t=n/2g. where v is the final velocity, g is the gravitational constant of 32 ft/sec sq, and t is the time of the fall. a skydiver jumps out of a plane at 6000 feet. how long did it take to reach the final velocity of -96 feet per second.

Given formula t= v/2g

Where v is the final velocity, g is the gravitational constant of 32 ft/sec^2, t is the time in seconds of the fall.

For the given problem, we have

g=-32 ft/sec^2 ( we took it negative because it's free fall and for free fall the value of g is a negative value).

v=-96 ft/sec.

Plugging values of v and g in given formula, we get

t= -96/2(-32)

t= -96/-64

Dividing -96 by -64, we get

t=1.5 seconds.

Therefore, it take 1.5 seconds to reach the final velocity of -96 feet per second.

The answer is 3 units.

12/4= 3

9/3= 3 units