![sash0924](/avatars/32677.jpg)
sash0924
27.02.2020 •
Mathematics
The top and bottom margins of a poster are 4 cm and the side margins are each 2 cm. If the area of printed materail on the poster is fixed at 380 cm^2, find the dimensions of the poster with teh smallest area
Solved
Show answers
More tips
- F Food and Cooking How to Make Mayonnaise at Home? Secrets of Homemade Mayonnaise...
- C Computers and Internet Which Phone is Best for Internet Surfing?...
- F Food and Cooking Everything You Need to Know About Pasta...
- C Computers and Internet How to Choose a Monitor?...
- H Horoscopes, Magic, Divination Where Did Tarot Cards Come From?...
- S Style and Beauty How to Make Your Lips Fuller? Ideas and Tips for Beautiful Lips...
- C Computers and Internet How to Learn to Type Fast?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
Answers on questions: Mathematics
- M Mathematics HELP SOS PLEASE A Different Temperature Scale There are other temperature scales besides Celsius and Fahrenheit. If you read Jules Verne s Journey to the Center...
- B Business To protect certain fledgling industries, the government of country Z banned imports of the types of products those industries were starting to make. As a direct...
- M Mathematics A new cola company is testing to see what proportion of their cans contain at least 12 oz. If they want to be within 3% of the actual percentage, how many cans...
- M Mathematics Which equation represents a line parallel to y - 2x = 8 Oy = 2x + 5 Oy = 10x - 3 Oy = 2x + 8 Oy = 6x + 2...
- M Mathematics The length of a rectangle is five inches less than twice its width. If the rectangle has a perimeter of 80 inches, find the length and width. * Width 5, Length...
Ответ:
The dimension of the poster are
length: √190 + 4 cm
heigth: √760 + 8 cm
Step-by-step explanation:
Let X be the length of the printed area and Y be the heigth. Then X*Y = 380. Note that Y = 380/X.
The length of the poster is x+2*2 = x+4 and the heigth is Y +4*2 = Y+8 = 380/X + 8. Thus, the area of the poster is
f(X) = (X+4)*(380/X +8) = 380 + 8X + 1520/X + 32 = 8x + 412 + 1520/X.
We want to minimize f(X), so we derivate it.
f'(x) = 8 + 0 - 1520/X² = 8-1520/X².
The derivate is equal to 0 when
8 = 1520/X²
X² = 1440/8 = 190
X = √190.
Thus Y = 380/√190 = √760.
The dimensions of the poster with the smallest area are:
length: √190 + 4 cm
heigth: √760 + 8 cm
Ответ:
B mores
C law
D a folkway
its A
trust me it A