The top and bottom margins of a poster are 8 cm and the side margins are each 6 cm. if the area of printed material on the poster is fixed at 390 square centimeters, find the dimensions of the poster with the smallest area.
the top and bottom margins of a poster are 8 cm an
width = (include units)
height = (include units)

Dimensions of the poster

Width  29.10 cm

Height 38.80 cm

A(min) = 1129.08 cm²

Step-by-step explanation:

Printed area = 390 cm² = Ap

Lets call x and y dimensions of printed area

x   width

y   height

Then Ap = x*y    and

y = Ap/x    ⇒    y = 390/x

Then   total area of the poster is:

A(t)  = ( x  + 12 ) * ( y + 16 )         and   y = 390/x

A as a function of x

A(x) = ( x  + 12 ) * ( 390/x + 16 )   ⇒  A(x) = 390 + 16x + 4680/x + 192

A(x) = 582 + 16x + 4680/x     (1)

Taking derivatives

A´(x) =  16 - (4680/x²)         ⇒ A´(x)  =  0

[ 16x² -4680] /x² = 0     16x²- 4680 = 0    ⇒     x² = 4680/16

x = 17.10 cm        and    y = 390/x      y = 390/17.10      y = 22.80 cm

A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )

A(t) = 29.10 * 38.80

A(t) = 1129.08 cm²

If we substitute  in equation (1) the value of x  ( 17.10) we see A(x) > 0

Then there is a minimun at the point x = 17.10

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

Step-by-step explanation:

Suppose that, in the past, 40% of all adults favored capital punishment. Test if the proportion has increased:

At the null hypothesis, we test if the proportion is still of 40%, that is:

At the alternative hypothesis, we test if the proportion has increased, that is, is greater than 40%, so:

The test statistic is:

In which X is the sample mean, is the value tested at the null hypothesis, is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that

Random sample of 15 adults, 8 favor capital punishment.

This means that

Value of the test statistic:

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion of 0.5333 or more, which is 1 subtracted by the p-value of z = 1.05.

Looking at the z-table, z = 1.05 has a p-value of 0.8531.

1 - 0.8531 = 0.1469.

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.